How do you write an equation of a line given point (1,-6) parallel to the line x+2y=6?
1 Answer
May 8, 2017
Explanation:
#" we require to know the following fact"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(" parallel lines have equal slopes")color(white)(2/2)|)))#
#"express " x+2y=6" in the form "color(red)(bar(ul(|color(white)(2/2)color(black)( y=mx+b)color(white)(2/2)|)))#
where m represents the slope and b, the y-intercept
#"subtract x from both sides"#
#cancel(x)cancel(-x)+2y=6-x#
#rArr2y=6-x#
#"divide ALL terms by 2"#
#(cancel(2) y)/cancel(2)=6/2-1/2x#
#rArry=-1/2x+3larr" in form " y=mx+b#
#rArr"slope "=m=-1/2#
#"using " m=-1/2" and the point " (1,-6)#
#rArry=-1/2x+b#
#"to find b, substitute point into equation"#
#-6=-1/2+brArrb=-11/2#
#rArry=-1/2x-11/2" is the equation"#
