How do you write an equation in standard form given a line that passes through (5,22) and (3,12)?

1 Answer
May 7, 2018

#5x-y=3#

Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

#"where A is a positive integer and B, C are integers"#

#"firstly, obtain the equation in "color(blue)"slope-intercept form"#

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"to calculate m use the "color(blue)"gradient formula"#

#•color(white)(x)m=(y_2-y_1)/(x_2-x_1)#

#"let "(x_1,y_1)=(5,22)" and "(x_2,y_2)=(3,12)#

#rArrm=(12-22)/(3-5)=(-10)/(-2)=5#

#rArry=5x+blarrcolor(blue)"is the partial equation"#

#"to find b substitute either of the 2 given points into"#
#"the partial equation"#

#"using "(3,12)" then"#

#12=15+brArrb=12-15=-3#

#rArry=5x-3larrcolor(red)"in slope-intercept form"#

#"subtract y and add 3 to both sides"#

#rArr5x-y=3larrcolor(red)"in standard form"#