How do you write an equation in standard form given a line that passes through (-5, 9) (3, -2)?

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Answer 1 · 2018-06-26T00:19:04

$8y + 11y = 17$

Given: $(-5, 9), (3, -2)$

Find the slope of the line: $m = (y_2 - y_1)/(x_2 - x_1) " or " m = (y_1 - y_2)/(x_1 - x_2)$

$m = (9 - -2)/(-5 - 3) = 11/-8 = -11/8$

Use $y = mx + b$ and one of the points to find $b$ , the $y$ -intercept:

$9 = -11/8 * -5/1 + b$

$9 = 55/8 + b$

$9/1 * 8/8 - 55/8 = b$

$b = (72 - 55)/8 = 17/8$

$y = -11/8 x + 17/8$

Standard form: $Ax + By = C$

Multiply the whole equation by $8: " "8y = -11x + 17$

$8y + 11y = 17$