How do you write an equation for these points (-3,-4),(6,-1)?

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Answer 1 · 2016-11-03T01:28:16

The line would have an equation of $y = 1/3x - 3$

We must start by finding the slope.

$m = (y_2 - y_1)/(x_2 - x_1)$

$m = (-1 - (-4))/(6 - (-3))$

$m = 3/9$

$m = 1/3$

Next, we use point-slope form to determine the equation of the line.

$y - y_1 = m(x - x_1)$

Let $(6, -1)$ be $(x_1, y_1)$ .

$y - (-1) = 1/3(x - 6)$

$y + 1 = 1/3x - 2$

$y = 1/3x - 2 - 1$

$y = 1/3x - 3$

Hopefully this helps!