How do you write an equation for these points (-3,-4),(6,-1)?

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Answer 1 · 2016-11-03T01:28:16

The line would have an equation of #y = 1/3x - 3#

We must start by finding the slope.

#m = (y_2 - y_1)/(x_2 - x_1)#

#m = (-1 - (-4))/(6 - (-3))#

#m = 3/9#

#m = 1/3#

Next, we use point-slope form to determine the equation of the line.

#y - y_1 = m(x - x_1)#

Let #(6, -1)# be #(x_1, y_1)#.

#y - (-1) = 1/3(x - 6)#

#y + 1 = 1/3x - 2#

#y = 1/3x - 2 - 1#

#y = 1/3x - 3#

Hopefully this helps!