How do you write an equation for the line that contains (-4,1) (6,1)?

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Answer 1 · 2018-04-13T02:38:44

$color(crimson)(y = 1, " is the equation of the line"$

$"Given : (x_1,y_1) = -4,1), (x_2,y_2) = (6,1)$

To obtain the equation of the line, we will use the formula

$(y - y_1) / (y_2 - y_1) = (x-x_1) / (x_2 - x_1)$

$(y - 1) / (1-1) = (x + 4) / (6 + 4)$

$(y-1) / 0 = (x +4) / 10$

$y - 1 = ((x+4)/10) * 0 = 0$

$:. y = 1, " is the equation of the line"$