How do you write an equation for a line passing through the points (5,-1) and (-3,-2)?

1 Answer
Binayaka C.
Jan 4, 2017

The equation of the line in standard form is # x -8y = 13#

Explanation:

The slope of the line passing through #(5,-1) and (-3,-2)# is #m= (y_2-y_1)/(x_2-x_1)= (-2+1)/(-3-5)=(-1)/(-8)=1/8#

Let the equation of the line in slope-intercept form be #y=mx+c or y=1/8x+c# The point (5,-1) will satisfy the equation . So, # -1= 1/8*5+c or c= -1-5/8= -13/8#

Hence the equation of the line in slope-intercept form is #y= 1/8x-13/8#

The equation of the line in standard form is #y= 1/8x-13/8. or 8y =x-13 or x -8y = 13# {Ans]

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