# How do you write a slope-intercept equation for a line parallel to the line x-2y=6 which passes through the point (-5,2)?

##### 2 Answers

#### Explanation:

We know,

If there are two equations of line like

then, the condition of they being parallel is

First Convert the line equation to the general form

Therefore,

Then, the equation of parallel line will be

If it passes through the point (-5, 2), then the equation will be satisfied with these values.

Lets put

Therefore,

Then the required equation will be

The equation, at slope-intercept form is

graph{y = (x + 9)/2 [-20.27, 20.26, -10.14, 10.13]}

#### Explanation:

#• " parallel lines have equal slopes"#

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"rearrange "x-2y=6" into this form"#

#rArry=1/2x-3larr" with "m=1/2#

#rArry=1/2x+blarrcolor(blue)"is the partial equation"#

#"to find b substitute "(-5,2)" into the partial equation"#

#2=-5/2+brArrb=9/2#

#rArry=1/2x+9/2larrcolor(red)"in slope-intercept form"#