How do you write a quadratic equation in standard form with the given roots 8, -2? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer NAGARAJA RAO H · Stefan V. Jul 16, 2016 #x^2 - 6x -16=0# Explanation: #(x-8)# and #(x+2)# are the factors of that quadratic equation. Multiply these two factors to the get the required quadratic equation. #(x-8)(x+2) = 0# #x^2-6x -16=0# Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is #x^2+3x^{\frac{1}{2}}# a polynomial? How do you express #-16+5f^8-7f^3# in standard form? What is the degree of #16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2#? What is the degree of the polynomial #x^4-3x^3y^2+8x-12#? What is the difference between a monomial, binomial and polynomial? How do you write #y = 2/3x + 5# in standard form? See all questions in Polynomials in Standard Form Impact of this question 42787 views around the world You can reuse this answer Creative Commons License