How do you write a polynomial function of least degree with integral coefficients that has the given zeros 5/3, 1, -1? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer Vinícius Ferraz May 24, 2017 #p(x) = 3x^3 -5x^2 - 3x + 5# Explanation: #(x - 5/3)(x - 1)(x + 1) = 0# #(3x - 5)(x^2 - 1) = 0# #3x^3 - 3x -5x^2 + 5 = 0# Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of #f(x) = 5x^7 − x + 216#? What are the zeros of #f(x)= −4x^5 + 3#? How many times does #f(x)= 6x^11 - 3x^5 + 2# intersect the x-axis? What are the real zeros of #f(x) = 3x^6 + 1#? How do you find the roots for #4x^4-26x^3+50x^2-52x+84=0#? What are the intercepts for the graphs of the equation #y=(x^2-49)/(7x^4)#? See all questions in Zeros Impact of this question 1767 views around the world You can reuse this answer Creative Commons License