How do you write a polynomial function of least degree and leading coefficient 1 when the zeros are 2i, -2i? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer Alan N. Sep 14, 2016 #f(x) = x^2+4# Explanation: Let #f(x)# be the polynomial of degree 2 and leading coefficient 1 with zeros #+-2i# Hence either #(x+2i)# or #(x-2i) = 0 # #:. f(x) = 0 = (x+2i)(x-2i)# #f(x) = x^2 +2ix -2ix -4i^2# #f(x) = x^2 +4# Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of #f(x) = 5x^7 − x + 216#? What are the zeros of #f(x)= −4x^5 + 3#? How many times does #f(x)= 6x^11 - 3x^5 + 2# intersect the x-axis? What are the real zeros of #f(x) = 3x^6 + 1#? How do you find the roots for #4x^4-26x^3+50x^2-52x+84=0#? What are the intercepts for the graphs of the equation #y=(x^2-49)/(7x^4)#? See all questions in Zeros Impact of this question 1148 views around the world You can reuse this answer Creative Commons License