How do you write 9.056 times 10^-4 in standard notation?

1 Answer
Aug 30, 2017

9.056xx10^(-4)=0.0009056

Explanation:

In scientific notation, we write a number so that it has single digit to the left of decimal sign and is multiplied by an integer power of 10.

In other words, in scientific notation, a number is written as axx10^n, where 1<=a<10 and n is an integer and 1<=a<10.

To write the number in normal or standard notation one just needs to multiply by the power 10^n (or divide if n is negative). This means moving decimal n digits to right if multiplying by 10^n and moving decimal n digits to left if dividing by 10^n (i.e. multiplying by 10^(-n)).

In the given case, as we have the number as 9.056xx10^(-4), we need to move decimal digit to the left by four points. For this, let us write 4.5 as 00009.056 and moving decimal point four points to left means 0.0009056

Hence in standard notation 9.056xx10^(-4)=0.0009056