How do you write 9.002 times 10^-5 in standard notation?

2 Answers
Shwetank Mauria
Aug 6, 2016

In standard notation 9.002xx10^(-5)=0.00009002

Explanation:

In scientific notation, we write a number so that it has single digit to the left of decimal sign and is multiplied by an integer power of 10.

In other words, in scientific notation, a number is written as axx10^n, where 1<=a<10 and n is an integer and 1<=a<10.

To write the number in normal or standard notation one just needs to multiply by the power 10^n (or divide if n is negative). This means moving decimal n digits to right if multiplying by 10^n and moving decimal n digits to left if dividing by 10^n (i.e. multiplying by 10^(-n)).

In the given case, as we have the number as 9.002xx10^(-5), we need to move decimal digit to the left by five points. For this, let us write 9.002 as 000009.002 and moving decimal point five points to left means 0.00009002

Hence in standard notation 9.002xx10^(-5)=0.00009002

Barney V.
Jan 22, 2017

0.00009002

Explanation:

9.002 xx 10^-5

=9 2/1000 xx 1/100000

=9002/1000 xx 1/100000

=9002.0/100000000

shift the decimal point 8 places to the left.

=0.00009002

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