How do you write #8.2 times 10^-4# in standard notation?

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Answer 1 · 2016-05-28T21:05:46

It is 0.00082.

The #10^-4# tells you that you have to write 4 zeros including the first one before the dot. So the number is
#8.2\times10^{-4}=0.00082#

Answer 2 · 2016-05-28T21:15:11

Emphasising the point made in the other solution

#8.2xx10^(-4)=0.00082#

Given: #8.2xx10^(-4)#

This is the same as

#8.2/(10xx10xx10xx10)#

#=0.82/(10xx10xx10)#

#=0.082/(10xx10)#

#=0.0082/(10)#

#=0.00082#