How do you write $6x^2 + 4x$ in factored form?

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Answer 1 · 2018-03-21T09:59:06

$color(green)(=> (sqrt6 x + 2 / sqrt6)^2 - 2/3$

$=> color(red)((sqrt6 x + 2/sqrt6 + sqrt(2/3)) * (sqrt6 x + 2/sqrt6 - sqrt(2/3))$

$6x^2 + 4x = 6x*2 + 4x + 4 / 6 - 4/6, " Add & Subtract 4/6"$

$=> (sqrt6x)^2 + 2 * (1/sqrt6) * 2 * x + (2/sqrt6)^2 - 2/3$

It is in the form $(a2 + 2ab + b^2) " where " a = sqrt6. b = 2 / sqrt6$

Hence $=> (sqrt6 x + 2 / sqrt6)^2 - (sqrt(2/3))^2$

It is again in the for $a^2 - b^2$

$=> (sqrt6 x + 2/sqrt6 + sqrt(2/3)) * (sqrt6 x + 2/sqrt6 - sqrt(2/3))$

Answer 2 · 2018-03-21T10:09:10

$2x(3x+2)$

$"take out a "color(blue)"common factor "2x$

$rArr6x^2+4x=2x(3x+2)$

How do you write 6x^2 + 4x 6x^2 + 4x in factored form?