How do you write $5y=10x-25$ in standard form and what is A, B, C?

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Answer 1 · 2017-04-14T16:33:32

#-10x + 5y +25= 0

General form or standard form is $Ax + By + C = 0$

So $5y = 10x - 25$ in standard form:

$-10x + 5y +25 = 0$

Where $A = -10, B = 5, C = 25$

Answer 2 · 2017-04-14T16:41:12

$2x-y=5$ , where $A=2, B=-1 and C=5$

The standard form of the equation of a straight line is:

$Ax+By=C$ , where $A>0$ , and if possible $A, B and C$ are relatively prime integers. Hence in this case:

$5y=10x-25$
$10x-5y=25$ , can be written as:
$2x-y=5$ => in standard form.

How do you write 5y=10x-255y=10x-25 in standard form and what is A, B, C?