How do you write #(5x^2 - 4x + 5) (3x^2 - 6x + 2)# in standard form?
1 Answer
Jan 17, 2017
Explanation:
We must ensure that each term in the second bracket is multiplied by each term in the first bracket. This is illustrated below.
#(color(red)(5x^2-4x+5))(3x^2-6x+2)#
#=color(red)(5x^2)(3x^2-6x+2)color(red)(-4x)(3x^2-6x+2)#
#color(white)(xxxx)color(red)(+5)(3x^2-6x+2)# distributing gives.
#15x^4-30x^3+10x^2-12x^3+24x^2-8x+15x^2-30x+10# collecting like terms.
#15x^4+(-30-12)x^3+(10+24+15)x^2+(-8-30)x+10#
#=15x^4-42x^3+49x^2-38x+10larr" in standard form"# Writing in standard form means, start with the term of the highest power of the variable, followed by terms with decreasing powers of the variable.
