How do you write $3x=4-3x^2$ in standard form?

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Answer 1 · 2018-03-28T00:22:03

$-3x^2-3x+4=0$

Standard forms of polynomials are in the form $ax^2+bx+c=0$ . The key realizations are:

a) We want to set the polynomial equal to zero
b) The exponents should descend from left to right

So, let's subtract $3x$ from both sides to set the equation equal to zero. We get:

$4-3x^2-3x=0$

This still isn't in standard form, since the exponents aren't in descending order. We can rewrite this as

$-3x^2-3x+4=0$

Which would be our final answer in standard form.

How do you write 3x=4-3x^23x=4-3x^2 in standard form?