How do you write #(-3x-1)(x+1)# in standard form?
1 Answer
Mar 13, 2016
Explanation:
multiply out the brackets. Each term in the 2nd bracket must be multiplied by each term in the 1st. To ensure this happens set out as follows :
#-3x(x + 1 ) - 1(x + 1 )#
# = -3x^2 - 3x - x - 1 = -3x^2 - 4x - 1 # Standard form is writing the expression , starting with the term that has the highest power of the variable followed by terms with decreasing powers until the last term , usually a constant.
# a_n x^n + a_(n-1) x^(n-1) + a_(n-2) x^(n-2) + ...... + a_0 x^0# hence :
#-3x^2 - 4x - 1 " is in standard form " #
