How do you write #2x^2 – 6x – 8 # in factored form? Algebra Polynomials and Factoring Factoring Completely 1 Answer Nallasivam V Sep 16, 2015 #2(x+1)(x-4)# Explanation: #2x^2-6x-8# #2(x^2-3x-4)# #2(x^2-4x+x-4# #2[x(x-4x)+1(x-4)]# #2(x+1)(x-4)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 4234 views around the world You can reuse this answer Creative Commons License