How do you write $2 sin (\frac{π}{6}) cos (\frac{π}{6})$ $2sin(pi/6)cos(pi/6)$ as a single trigonometric function?

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Answer 1 · 2016-07-20T12:13:15

$sin (\frac{π}{3})$ $sin(pi/3)$ .

$sin 2 θ = 2 sin θ cos θ$ $sin2theta=2sinthetacostheta$

Hence, $2 sin (\frac{π}{6}) cos (\frac{π}{6}) = sin (2 \frac{π}{6}) = sin (\frac{π}{3})$ $2sin(pi/6)cos(pi/6)=sin(2pi/6)=sin(pi/3)$ .

How do you write 2sin(pi/6)cos(pi/6)2sin(π6)cos(π6)2sin(pi/6)cos(pi/6) as a single trigonometric function?