How do you write #2(cos300+isin300) in retangular form?

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Answer 1 · 2015-02-03T10:03:13

The answer is: #z=1-sqrt3i#.

The rectangular form of a complex number is:

#z=a+ib#,

and we have a number written in trigonometric form, that is:

#z=rho(sintheta+icostheta)#.

So the real part of the numer is #rhosintheta=2cos300°=2*1/2=1# and the imaginary part is #2sin300°=2*(-sqrt3/2)=-sqrt3#.

So:

#z=1-sqrt3i#.