Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you write #2 - 3i# in trigonometric form?

1 Answer

Jan 27, 2016

#2-3i = sqrt(13)(cos theta +isin theta)#

Explanation:

See Trigonometric form for a demonstration of how to do this.

In order to write a complex number #2 - 3i# in trigonometric form we need to find the modulus #z#, where #z = a +bi = |z|(cos theta + i sin theta)#

#z=sqrt(a^2+b^2) = sqrt(2^2 +(-3)^2) =sqrt(13)#

Then #2-3i = sqrt(13)(cos theta +isin theta)#

Related questions

See all questions in The Trigonometric Form of Complex Numbers

Impact of this question

2689 views around the world

You can reuse this answer
Creative Commons License