How do you write $11t+2t^2-3+t^5$ in standard form and what is the leading coefficients?

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Answer 1 · 2017-04-16T03:04:31

See the solution explanation below:

To write this expression in standard form we put the terms in order of the highest exponent to lowest:

$11t + 2t^2 - 3 + t^5$ becomes:

$t^5 + 2t^2 + 11t - 3$

The leading coefficient for the $t^5$ term is $1$ :

$1t^5 + 2t^2 + 11t - 3$

How do you write 11t+2t^2-3+t^511t+2t^2-3+t^5 in standard form and what is the leading coefficients?