How do you write #1/2+5i # in polar form and find ?

1 Answer
Binayaka C.
Feb 12, 2016

#z = 5.025* (cos 1.47 +isin 1.47)# Angle expressed in radians.

Explanation:

In polar form #(1/2+5*i)# lies on the 1st quardrant. The length of it from the origin is # r = sqrt(.5^2+5^2) = sqrt 25.25 = 5.025# The argument is #theta=tan^-1 (5/.5) or theta = tan^-1 10 = 1.47 radian#
So in Polar form #z = 5.025* (cos 1.47 +isin 1.47)# ; If #theta# is expressed in degree then #z = 5.025* (cos 84.29 +isin 84.29)#

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