How do you use the Squeeze Theorem to find $lim (x^2)(cos20(pi*x))$ as x approaches zero?

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Answer 1 · 2015-09-27T03:56:28

Refer to explanation

W know that

$-1<=cos(20pix)<=1=>-x^2<=x^2cos(20pix)<=x^2$

Hence using the squeeze theorem since

$lim_(x->0)-x^2=lim_(x->0)x^2=0$

then

$lim_(x->0) x^2cos(20pix)=0$

How do you use the Squeeze Theorem to find lim (x^2)(cos20(pi*x)) lim (x^2)(cos20(pi*x)) as x approaches zero?