How do you use the remainder theorem to find the remainder for each division #(2x^3-3x^2+x)div(x-1)#?

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Answer 1 · 2017-05-17T08:03:06

#0#

The remainder theorem states that if you divide #P(x)# by #(x-a)#

the remainder will be #P(a)#

so dividing #P(x)=(2x^3-3x^2+x)" "#by #" "(x-1)#

will give a remainder of #P(1)#

#P(1)=2xx1^3-3xx1^2+1#

#P(1)=2-3+1=0#

which means that in this case #(-1)# is a factor of #P(x)#