How do you use the pythagorean theorem to solve a=x-5 b=x 2 c=13?

Question

How do you use the pythagorean theorem to solve a=x-5 b=x 2 c=13?

1 Answer

Impact of this question

2120 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-22T17:10:24

So acceptable value of x is 10

Explanation:

Here sides are
#a=x-5#
#b=x+2#
#c=13#
Taking c as larger side i.e. hypotenuse
we can apply Pythagorean theorem

#a^2+b^2=c^2#
#=>(x-5)^2+(x+2)^2=13^2#
#=>(x^2-10x+25+x^2+4x+4)=169#
#=>(2x^2-6x-140)=0#
#=>x^2-3x-70=0#
#=>x^2-10x+7x-70=0#
#=>x(x-10)+7(x-10)=0#
#=>(x-10)(x+7)=0#
So acceptable value of x is 10
otherwise a and b will be negative for x = -7

Science

Math

Humanities

... and beyond

How do you use the pythagorean theorem to solve a=x-5 b=x 2 c=13?

1 Answer

Explanation:

Related questions

Impact of this question