How do you use the properties of logarithms to rewrite and simplify the logarithmic expression of #2log8^4-1/3log8^8#?

1 Answer
MeneerNask
May 16, 2015

First you may put all exponents in the log-argument in front of the log:

#=4*2log8-8*1/3log8# then we can combine:

#=(8-8/3)log8=16/3log8#

If we consider that #8=2^3# we can take this exponent out as well:

#=16/3 log2^3=3*16/3log2=16log2#

Of course you could do the #2^3# thing first. The order of operations does not really matter.

Related questions
See all questions in Common Logs
Impact of this question
1715 views around the world
You can reuse this answer
Creative Commons License