How do you use the point (-9,14) on the terminal side of the angle to evaluate the six trigonometric functions?

Question

How do you use the point (-9,14) on the terminal side of the angle to evaluate the six trigonometric functions?

1 Answer

Impact of this question

1706 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-19T01:21:58

The terminal side, containing point (-9, 14), is in Quadrant 3.
Call t the angle.
$tan t = -14/9$
$cos^2 t = 1/(1 + tan^2 t) = 1/(1 + 196/81) = 81/277$
$cos t = +- 9/sqrt277$
Because t is in Quadrant 3, cos t is negative -->
$cos t = - 9/(sqrt277)$
$sin t = tan t.cos t = (-14/9)(-9/sqrt277) = 14/sqrt277$
$tan t = -14/9$
$cot t = - 9/14$
$sec t = 1/(cos) = - sqrt277/9$
$csc t = 1/(sin) = sqrt277/14$

Science

Math

Humanities

... and beyond

How do you use the point (-9,14) on the terminal side of the angle to evaluate the six trigonometric functions?

1 Answer

Related questions

Impact of this question