How do you use the point (-6,-8) on the terminal side of the angle to evaluate the six trigonometric functions?

1 Answer
Douglas K.
Oct 14, 2016

sin(x) = -4/5
csc(x) = -5/4
cos(x) = -3/5
sec(x) = -5/3
tan(x) = 4/3
cot(x) = 3/4

Explanation:

let o represent length of the opposite side:

o = -8

let a represent the length of the adjacent side:

a = -6

The length of the hypotenuse is:

h = sqrt((-6)^2 + (-8)^2)

h = 10

sin(x) = o/h = -8/10 = -4/5
csc(x) = 1/sin(x) = -5/4
cos(x) = a/h = -6/10 = -3/5
sec(x) = 1/cos(x) = -5/3
tan(x) = o/a = (-8)/-6 = 4/3
cot(x) = 1/tan(x) = 3/4

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