How do you use the direct Comparison test on the infinite series sum_(n=2)^oon^3/(n^4-1) ?

1 Answer
Wataru
Sep 8, 2014

Since n^3/{n^4-1} geq n^3/n^4=1/n for all n geq2 and sum_{n=2}^infty1/n is a harmonic series, which is known to be divergent, we may conclude that sum_{n=2}^inftyn^3/{n^4-1} also diverges by Direct Comparison Test.

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