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How do you use substitution to integrate #cos x/sin x dx#?

1 Answer

Jul 29, 2015

The procedure is outlined below.

Explanation:

We have to evaluate, #int Cos x/Sin x * dx#

So, let #Sin x = t#
#implies Cos x*dx = dt# (By simple differentiation)

Thus the integral #int Cos x/Sin x *dx = int dt/t#
#= Ln t + C#

In terms of #x#, the integral is,

#int Cos x/Sin x * dx = Ln (Sin x) + C#, where #C# is the integration constant.

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