How do you use Heron's formula to determine the area of a triangle with sides of that are 28, 29, and 42 units in length?
1 Answer
Apr 5, 2016
≈ 404.51 square units
Explanation:
This is a 2 step process.
step 1 : Calculate half the perimeter (s) of the triangle
let a = 28 , b = 29 and c = 42
then s
= (a+b+c)/2 = (28+29+42)/2 = 99/2 = 49.5 =a+b+c2=28+29+422=992=49.5 step 2 : Calculate the area (A) using
A = sqrt(s(s-a)(s-b)(s-c)) A=√s(s−a)(s−b)(s−c)
= sqrt(49.5(49.5-28)(49.5-29(49.5-42))=√49.5(49.5−28)(49.5−29(49.5−42))
= sqrt(49.5xx21.5xx20.5xx7.5) ≈ 404.51" square units " =√49.5×21.5×20.5×7.5≈404.51 square units
