How do you use FOIL to multiply #(x+2)^3#?

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Answer 1 · 2015-06-06T00:06:44

FOIL will only get you part of the way,

First + Outside + Inside + Last ...

#(x+2)(x+2) = (x*x)+(x*2)+(2*x)+(2*2)#

#=x^2+2x+2x+4#

#=x^2+4x+4#

Then

#(x^2+4x+4)(x+2)#

#= (x^2+4x+4)*x + (x^2+4x+4)*2#

#=x^3+4x^2+4x + 2x^2+8x+8#

#=x^2+6x^2+12x+8#