How do you use cross products to solve #4/p=14/28#?

1 Answer
Jim G.
Aug 25, 2017

#p=8#

Explanation:

#"using the method of "color(blue)"cross-products"#

#•color(white)(x)a/b=c/drArrad=bc#

#rArr4/p=14/28#

#rArr14p=4xx28#

#rArrp=(4xxcancel(28)^2)/cancel(14)^1==4xx2=8#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#"left side "=4/8=1/2#

#"right side "=14/28=1/2#

#rArrp=8" is the solution"#

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