How do you take the derivative of tan^ -1(3x^2)?
1 Answer
Jun 23, 2018
Explanation:
"differentiate using the "color(blue) "chain rule"
"given "y=f(g(x))" then"
dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"
"noting that "d/dx(tan^-1x)=1/(1+x^2)
d/dx(tan^-1(3x^2))
=1/(1+(3x^2)^2)xxd/dx(3x^2)
=(6x)/(1+9x^4)
