How do you subtract #(3x^3 – 4x^2 + 6x) – (5x^3 + 2x^2 – 3x)#?

1 Answer
Watchmojo J.
Apr 13, 2018

#-2x^3-6x^2+9x#

Explanation:

#(3x^3–4x^2+6x)–(5x^3+2x^2–3x)#

#–(5x^3+2x^2–3x)#
#=–1xx(5x^3+2x^2–3x)#
#=(–1xx5x^3)+(–1xx2x^2)+(–1xx–3x)#
#=–5x^3-2x^2+3x#

#=3x^3–4x^2+6x" "color(blue)(–5x^3-2x^2+3x)#

#=3x^3color(blue)(–5x^3)–4x^2color(blue)(-2x^2)+6xcolor(blue)(+3x)#

#=color(red)(-2x^3-6x^2+9x)#

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