How do you subtract #10-6 3/8#?

1 Answer
smendyka
Jan 7, 2017

See full process below:

Explanation:

First, we need to convert the mixed fraction to an improper fraction. We do this by multiplying the integer portion of the mixed fraction by the appropriate form of #1# and then adding this result to the fraction portion of the improper fraction:

#10 - ((8/8 xx 6) + 3/8) ->#

#10 - (48/8 + 3/8)#

#10 - 51/8#

Next we need to get the two terms over a common denominator (8 in this case) so we can subtract the fractions. We do this by multiplying #10# by the appropriate form of #1# again.

#(8/8 xx 10) - 51/8#

#80/8 - 51/8#

#(80 - 51)/8#

#29/8#

Or

#(24 + 5)/8 = 24/8 + 5/8 = 3 + 5/8 = 3 5/8#

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