How do you find the zeros of $y=-x^2+4x-4$ ?

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Answer 1 · 2014-11-06T18:09:32

By setting it equal to zero,

$-x^2+4x-4=0$

by multiplying by $-1$ ,

$=> x^2-4x+4=0$ ,

by factoring out,

$=> (x-2)^2=0$

Hence, $x=2$ is the zero of the function.

I hope that this was helpful.

How do you find the zeros of y=-x^2+4x-4y=-x^2+4x-4?