How do you solve #y= 2 log(x)#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Binayaka C. Mar 18, 2018 #x=sqrt(10^y)# Explanation: #y= 2log x or y= log x^2; [log x^m=mlogx]# # :. x^2=10^y :. x=sqrt(10^y ); # # [log _b (N)=x # , then #b^x=N]# [Ans] Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 23261 views around the world You can reuse this answer Creative Commons License