How do you solve #x-y=6# and #2x + 3y =2# using matrices?

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Answer 1 · 2017-09-28T16:24:58

The solution is #((x),(y))=((4),(-2))#

Let's perfom the Gauss-Jordan elimination on the augmented matrix

The augmented matrix is

#((1,-1,|,6),(2,3,|,2))#

Let`s perform the row operations

#R2larr(R2-2R1)#

#((1,-1,|,6),(0,5,|,-10))#

#R2larr(R2)/(5)#

#((1,-1,|,6),(0,1,|,-2))#

#R1larr(R1+R2)#

#((1,0,|,4),(0,1,|,-2))#

The solution is #((x),(y))=((4),(-2))#

Answer 2 · 2017-10-13T23:10:10

#x=4, y=-2#

enter image source here
#x=4, y=-2#