How do you solve #x=log_12 144#?

1 Answer
KillerBunny
Dec 2, 2015

#x=2#

Explanation:

Even if there's nothing to "solve", strictly speaking, I assume you simply want to simplify #log_{12}(144)#, and it's very simple:

#log_{a}(b)=x# means that #x# is the exponent that you must give to #a# to obtain #b#. Namely: #a^x=b#.

This means that, in your case, #log_{12}(144)# is the exponent that you must give to #12# to obtain #144#, and since #144=12^2#, that exponent is #2#. So,

#x=log_{12}(144)=2#

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