How do you solve #x+8<=3##?

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Answer 1 · 2018-05-14T11:51:36

#x+8<=3# when #x<=-5# (subtract 8 from each side of the inequality)

If 8 more than something ( #x# ) should be equal or less than 3, how much can then the "something" (i.e. #x#) be?

Thinking this way, I think you can see that the answer is 8 less than 3, i.e. #-5#

Formally we solve it this way:
#x+8<=3#
#x+8-8<=3-8# (we subtract 8 from both sides)
#x<=-5#

Graphically we can solve it this way:
Draw a graph of the function #y=x+8#:

enter image source here

Draw a line parallell til the #x# axis through 5 on the #y# axis.

For which values of x are the y function less than or equal to 3?

From the diagram we see that #y=x+8# is #<= 3# when #x<=-5#