How do you solve #x+5=28#?
1 Answer
Apr 8, 2018
Explanation:
#"to isolate x subtract 5 from both sides of the equation"#
#xcancel(+5)cancel(-5)=28-5#
#rArrx=23" is the solution"#
#"to isolate x subtract 5 from both sides of the equation"#
#xcancel(+5)cancel(-5)=28-5#
#rArrx=23" is the solution"#