How do you solve (x3−4x2−11x+30)÷(x−2)?
2 Answers
Jan 29, 2018
Explanation:
Jan 29, 2018
Explanation:
one way is to use the divisor as a factor in the numerator
consider the numerator
x2(x−2)+2x2−4x2−11x+30
=x2(x−2)−2x(x−2)−4x−11x+30
=x2(x−2)−2x(x−2)−15(x−2)−30+30
=x2(x−2)−2x(x−2)−15(x−2)+0
quotient =x2−2x−15, remainder=0
⇒x3−4x2−11x+30x−2=x2−2x−15