How do you solve (x+3)/3=(10+4)/4x+33=10+44?

1 Answer
Aug 22, 2017

See a solution process below:

Explanation:

First, we can simplify the right side of the equation:

(x + 3)/3 = 14/4x+33=144

(x + 3)/3 = (2 xx 7)/(2 xx 2)x+33=2×72×2

(x + 3)/3 = (color(red)(cancel(color(black)(2))) xx 7)/(color(red)(cancel(color(black)(2))) xx 2)

(x + 3)/3 = 7/2

Next, we can multiply each side of the equation by color(red)(3) to eliminate the fraction on the left side of the equation while keeping the equation balanced:

color(red)(3)(x + 3)/3 = color(red)(3) xx 7/2

cancel(color(red)(3))(x + 3)/color(red)(cancel(color(black)(3))) = 21/2

x + 3 = 21/2

Now, we can subtract color(red)(3) from each side of the equation to solve for x while keeping the equation balanced:

x + 3 - color(red)(3) = 21/2 - color(red)(3)

x + 0 = 21/2 - (2/2 xx color(red)(3))

x = 21/2 - 6/2

x = (21 - 6)/2

x = 15/2