How do you solve $x-2(x+10)=12$ ?

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Answer 1 · 2018-05-10T21:37:53

$x=-32$

Expand the brackets

$x-2(x + 10)=12 => x-2x-20=12$

$-x-20=12$

Add $x$ to both sides

$-20=12+x$

Subtract 12 from both sides

#-32=x

How do you solve x-2(x+10)=12x-2(x+10)=12?