How do you solve x^2+9x+20.25=0 by completing the square?
1 Answer
Dec 18, 2016
Explanation:
The left hand side is already a perfect square trinomial:
(x+9/2)^2 = x^2+9x+81/4 = x^2+9x+20.25
So the given equation is equivalent to:
(x+9/2)^2 = 0
Hence:
x+9/2 = 0
Hence:
x = -9/2