How do you solve #x^2+9x+20.25=0# by completing the square?
1 Answer
Dec 18, 2016
Explanation:
The left hand side is already a perfect square trinomial:
#(x+9/2)^2 = x^2+9x+81/4 = x^2+9x+20.25#
So the given equation is equivalent to:
#(x+9/2)^2 = 0#
Hence:
#x+9/2 = 0#
Hence:
#x = -9/2#