How do you solve $x^2+6x>=0$ using a sign chart?

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Answer 1 · 2018-02-18T12:30:00

Solution: $x <= -6 and x >=0$ . In interval notation:

$x| (-oo,-6]uu [0,oo)$

$x^2+6x>=0 or x(x+6) >=0$

Critical points are $x=0 and x=-6$

Sign chart:

When $x <=-6$ sign of $f(x)$ is $(-)(-)=(+) ; >=0$

When $-6 < x <0$ sign of $f(x)$ is $(-)(+)=(-) ; <0$

When $x >=0$ sign of $f(x)$ is $(+)(+)=(+) ; >=0$

Solution: $x <= -6 and x >=0$ . In interval notation:

$x| (-oo,-6]uu [0,oo)$

graph{x^2+6x [-20, 20, -10, 10]} [Ans]

How do you solve x^2+6x>=0x^2+6x>=0 using a sign chart?