How do you solve $\frac{x + 2}{6} = \frac{x - 1}{12}$ $(x+2)/6=(x-1)/12$ ?

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How do you solve $\frac{x + 2}{6} = \frac{x - 1}{12}$ $(x+2)/6=(x-1)/12$ ?

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Answer 1 · 2017-10-08T08:40:50

$x = - 5$ $x=-5$

Explanation:

By cross multiplication,
$12 (x + 2) = 6 (x - 1)$ $12(x+2)=6(x-1)$
$12 x + 24 = 6 x - 6$ $12x+24=6x-6$
$12 x - 6 x = - 24 - 6$ $12x-6x=-24-6$
$6 x = - 30$ $6x=-30$
Divide both sides by $6$ $color(red)(6)$
$cancel(6x)/cancelcolor(red)(6) = (-30)/color(red)(6)$
$x=-5$

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How do you solve $\frac{x + 2}{6} = \frac{x - 1}{12}$ $(x+2)/6=(x-1)/12$ ?

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